Therefore, in this instance, we have no grounds to reject the null hypothesis that states there is no association between level of education and dog ownership. The Pearson Chi-Square test statistic (3.589) similarly does not reach significance. Normally this would not be considered significant (given an alpha level of. It’ll look something like this.Īs you can see above, the value of the Fisher’s exact test statistic is 3.286.
![spss 25 vs 22 spss 25 vs 22](https://itservices.usc.edu/files/2011/11/licensespssmac3.png)
You can view the test result in the SPSS output viewer. Press Continue, and then OK to run the test. Hit the Exact button (top right within the Crosstabs dialog), and choose the Exact option, leaving the test time limit as it is. You should now be back at the Crosstabs dialog. Press Continue when you’ve made the selection. To do this, click on Statistics, and choose the Chi-square option. The first stage in configuring SPSS to run Fisher’s exact test is to set up a chi square test. You can drag and drop, or use the arrows, as above. It doesn’t matter which variable goes into which box. One of these goes into the Row box, and the other into the Column box. If you have more than two, as in our example, you need to identify which of the two you want to test for independence. To start, click on Analyze -> Descriptive Statistics -> Crosstabs.
![spss 25 vs 22 spss 25 vs 22](https://windows-cdn.softpedia.com/screenshots/IBM-SPSS-Amos_1.png)
The procedure for doing Fisher’s exact test in SPSS is similar to that used for the chi square test. Our data looks like this in the SPSS Data View.